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Standard XII

Chemistry

SHE

The standard ...

Question

The standard cell potential for $Z n | Z n^{2 +} | | C u^{2 +} | C u$ is 1.10V. When the cell is completely discharged, $l o g [Z n^{2 +}] / [C u^{2 +}]$ is closest to:

37.3

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0.026

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18.7

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Solution

The correct option is A 37.3
$Z n | Z n^{2 +} | | C u^{2 +} | C u$ ;
$0 = E_{c e l l}^{0} - \frac{0.0591}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$

$l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]} = \frac{2.2}{0.0591} = 37.3$
$E_{c e l l}^{0} = 1.1 V$

$- 1.1 = - \frac{0.0591}{2} l o g_{10} \frac{[Z n^{2 +}]}{[C u^{2 +}]}$

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The standard cell potential for Zn|Zn2+||Cu2+|Cu is 1.10V. When the cell is completely discharged, log[Zn2+]/[Cu2+] is closest to:

The correct option is A 37.3Zn|Zn2+||Cu2+|Cu;0=E0cell−0.05912log[Zn2+][Cu2+]log[Zn2+][Cu2+]=2.20.0591=37.3E0cell=1.1V−1.1=−0.05912log10[Zn2+][Cu2+]

The standard cell potential for $Z n | Z n^{2 +} | | C u^{2 +} | C u$ is 1.10V. When the cell is completely discharged, $l o g [Z n^{2 +}] / [C u^{2 +}]$ is closest to: