Question

The standard deviation of first 10 natural numbers is

• A. 5.5
• B. 3.87
• C. 2.97
• D. 2.87

Answer 1

The correct option is D

2.87

We know that the standard deviation of first n natural number is $\sqrt{\frac{n^2-1}{12}}$

$\therefore$ Standard deviation of first 10 natural numbers.

= $\sqrt{\frac{{10}^2-1}{12}}$

= $\sqrt{\frac{99}{12}}=\sqrt{8.25}=2.87$

Hence, the correct answer is option (d).