The standard deviation of the data $6, 5, 9, 13, 12, 8, 10$ is

\sqrt{\frac{52}{7}}

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\frac{52}{7}

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\sqrt{6}

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6

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Solution

The correct option is D $\sqrt{\frac{52}{7}}$
Given observation is, 6,5,9,13,12,8,10.
Here $n = 7, \sum x_{i} = 63, \sum x_{i}^{2} = 619$
$∴$ Required standard deviation is $σ = \sqrt{\frac{\sum x_{i}^{2}}{n} - {(\frac{\sum x_{i}}{n})}^{2}} = \sqrt{\frac{52}{7}}$

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Similar questions

\sqrt{6}

\frac{52}{7}

\sqrt{\frac{52}{7}}

The standard deviation of the observations 6,5,9,13,12,8,10 is

$x$	$3$	$4$	$5$	$6$	$7$
$f$	$12$	$35$	$52$	$41$	$18$

3, 5, 6, 7

4

62, 58, 53, 50, 63, 52, 55

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