The standard $E_{r e d}^{\circ}$ values of $A, B$ and $C$ are $+ 0.68 V, - 2.54 V$ and $- 0.50 V$ respectively. The order of their reducing power is:

A > B > C

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A > C > B

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C > B > A

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B > C > A

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Solution

The correct option is C $B > C > A$
$E_{r e d u c t i o n}^{\circ} \propto \frac{1}{reducing power of element}$
$∴$ The order of this reducing power $= B > C > A .$

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A, B

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+ 0.68 V, - 2.54 V, - 0.50 V

For elements A, B and C the standard reduction potential are +0.65V , -2.25V and -0.45V respectively. The correct order of their reducing power is:

E^{\circ}

The standard electrode potential values of the elements A,B and C are 0.68, 2.5V and 0.5V respectively the order of their reducing power is :

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