The standard electrode potential Eol2/r,E0Br−/Br2andE0Fe/Fe2+ are respectively +0.54V,-1.09V and 0.44V. On the basis of above data which of the following process is non spontaneous?
A
Br2+2I1⟶2Br+I2
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B
Fe+Br2⟶Fe2++2Br
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C
Fe+I2⟶Fe2++2I−
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D
I2+Br⟶2I−+Br2
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Solution
The correct option is CBr2+2I1⟶2Br+I2 We know that,
ΔG=−nFEcell, if ΔG>0 the, the reaction is said to be spontaneous.For that, Ecell>0
In the given options considering option A,
Ecell=Ecathode−Eanode=−0.54−1.09=−1.63V
So the value of Ecell>0 and hence the reaction will be non-spontaneous.