The standard electrode potential of Zn2+|Zn is −0.76V and that of Cu2+|Cu is 0.34V. The emf (V) and the free energy change (kJmol−1), respectively, for a Daniel cell will be:
A
−0.42 and 81
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B
1.1 and −213
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C
−1.1 and 213
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D
0.42 and −81
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Solution
The correct option is B1.1 and −213 E0Cell=E0Cu2+/Cu−E0Zn2+/Zn=0.34−(−0.76)=1.1V