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The standard ...

Question

The standard electrode potential values, $E^{o}$ , for $A l^{3 +} / A l$ and $T l^{3 +} / T l$ are $- 1.66 V$ and $+ 1.26 V$ respectively. Select the correct statement.

Aluminium has a high tendency to form

A l^{3 +}

as compared to thallium

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T l^{3 +}

is a powerful reducing agent

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Thallium is more electropositive than aluminium

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Thallium has a high tendency to form

T l^{3 +} (a q)

as compared to Aluminium

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Solution

The correct option is A Aluminium has a high tendency to form $A l^{3 +}$ as compared to thallium
As can be seen from the standard electrode potentials of the two given half cells, aluminium has a high tendency to form $A l^{3 +} (a q)$ ions as compared to $T l^{3 +}$ . $T l^{3 +}$ is unstable in solution and it acts as a powerful oxidising agent. Aluminium being able to form $+ 3$ ions easily, is more electropositive than thallium.

Suggest Corrections

Similar questions

F e_{(a q)}^{3 +} + e^{-} \to F e_{(a q)}^{2 +}

E^{o} = + 0.77

A l_{(a q)}^{3 +} + 3 e^{-} \to A l_{s}; E^{o} = - 1.66

B r_{2 (a q)} + 2 e^{-} \to 2 B r_{(a q)}^{-}; E^{o} = + 1.66

What is the standard potential of the $T l^{3 +} / T l$ electrode?

$T l^{3 +} + 2 e^{-} \to T l^{+} E^{0} = 1.26 V T l^{+} + e^{-} \to T l E^{0} = - 0.336 V$

T l^{3 +} / T l

T l^{3 +} + 2 e^{-} \to T l^{+}; E^{\circ} = 1.26 v o l t

T l^{+} + e^{-} \to T l; E^{\circ} = - 0.336 v o l t

(E^{o})

O {C l}^{-} / {C l}^{-}

{C l}^{-} / \frac{1}{2} {C l}_{2}

0.94 V

- 1.36 V

E^{o}

O {C l}^{-} / {C l}_{2}

(E^{o}

)

\begin{matrix} E l e m e n t - -------- - & M^{3 +} / M - ------- - & M^{+} / M - ------ - A l & - 1.66 & + 0.55 T l & + 1.26 & - 0.34 \end{matrix}

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