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Standard XII

Chemistry

Gibb's Energy and Nernst Equation

The standard ...

Question

The standard electrode potentials, K⁺/K= -2.93V, Ag⁺/Ag = 0.80V, the electrode which is negatively charged is

Ag⁺/Ag

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K⁺/K

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Any of the two

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None of them

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Solution

The correct option is B
K⁺/K

Here K⁺/K is undergoing oxidation so it is anode and is negatively charged.

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Similar questions

Given the standard electrode potentials,
$K^{+} / K = - 2.93 V, A g^{+} / A g = 0.80 V, H g^{2 +} / H g$
$= 0.79 V$
$M g^{2 +} / M g = - 2.37 V . C r^{3 +} / C r = - 0.74 V$
Arrange these metals in their increasing order of reducing power.

The standard electrode potentials are K⁺/K= -2.93V, Ag⁺/Ag = 0.80 V, so

Q. Given are the standard electrode potentials of few half-cells. The correct order of these metals in increasing reducing power will be:

K^{+} / K = - 2.93 V, A g^{+} / A g = 0.80 V

M g^{2 +} / M g = - 2.37 V, C r^{3 +} / C r = - 0.74 V

Q. Given the standard electrode potentials of some metals.

K^{+} / K = - 2.93 V

A g^{+} / A g = 0.80 V

H g^{2 +} / H g = 0.79 V

M g^{2 +} / M g = - 2.37 V

and

C r^{3 +} / C r = - 0.74 V

Arrange these metals in their increasing order of reducing power.

Q. The standard reduction potential of

A g^{+} / A g

electrode at

298 K

0.799 v o l t

. Given for

A g l, K_{s p} = 8.7 \times 10^{- 17}

, evaluate the potential of the

A g^{+} / A g

electrode in a saturated solution of

A g l

. Also calculate the standard reduction potential of the

I^{-} / A g I / A g

electrode.

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The standard electrode potentials, K+/K= -2.93V, Ag+/Ag = 0.80V, the electrode which is negatively charged is

The correct option is B K+/K Here K+/K is undergoing oxidation so it is anode and is negatively charged.

The standard electrode potentials, K⁺/K= -2.93V, Ag⁺/Ag = 0.80V, the electrode which is negatively charged is

The correct option is B
K⁺/K

Here K⁺/K is undergoing oxidation so it is anode and is negatively charged.