The standard emf of galvanic cell involving $3$ moles of electrons in its redox reaction is $0.59 V$ . The equilibrium constant for the reaction of the cell is:

10^{25}

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10^{20}

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10^{15}

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10^{30}

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Solution

The correct option is D $10^{30}$
The standard emf of a galvanic cell involving $3$ moles of electrons in its redox reaction is $0.59 V$ .
$E_{c e l l}^{o} = 0.59 V$

$n = 3$

The equilibrium constant for the reaction of the cell is given by the expression

$l n K = \frac{n F E_{c e l l}^{o}}{R T}$

$l n K = \frac{3 \times 96500 \times 0.59}{8.314 \times 298}$

$l n K = 68.9$

$K \approx 10^{30}$

The equilibrium constant for the reaction of the cell is $10^{30}$ .

Hence, the correct answer is option $D$ .

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The standard emf of galvanic cell involving 3 moles of electrons in its redox reaction is 0.59 V. The equilibrium constant for the reaction of the cell is:

The standard emf of galvanic cell involving $3$ moles of electrons in its redox reaction is $0.59 V$ . The equilibrium constant for the reaction of the cell is: