The standard enthalpy of formation of ammonia gas is
Given : N2H4(g)→2NH3(g);
ΔH∘r=−40kJ/mol and ΔH∘f[N2H4(g)]=−120kJ/mol
A
-60
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B
-180
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C
40
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D
-80
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Solution
The correct option is D -80 Given: N2H4(g)→2NH3(g);ΔH∘r=−40kJ/mol ΔH∘f[N2H4(g)]=−120kJ/mol. ΔH∘r=2ΔH∘f[NH3(g)]−ΔH∘f[N2H4(g)]=2x−(−120). 2x=−40+(−120),x=80kJ/mol.