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Question
The standard enthalpy of formation of ammonia gas is
Given : N2H4(g)→2NH3(g);ΔH∘r=−40kJ/mol and ΔH∘f[N2H4(g)]=−120kJ/mol
The standard enthalpy of formation of ammonia gas is
Given : N2H4(g)→2NH3(g);
ΔH∘r=−40kJ/mol and ΔH∘f[N2H4(g)]=−120kJ/mol
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Solution
The correct option is D -80
Given:
N2H4(g)→2NH3(g);ΔH∘r=−40kJ/mol
ΔH∘f[N2H4(g)]=−120kJ/mol.
ΔH∘r=2ΔH∘f[NH3(g)]−ΔH∘f[N2H4(g)]=2x−(−120).
2x=−40+(−120),x=80kJ/mol.
Given:
N2H4(g)→2NH3(g);ΔH∘r=−40kJ/mol
ΔH∘f[N2H4(g)]=−120kJ/mol.
ΔH∘r=2ΔH∘f[NH3(g)]−ΔH∘f[N2H4(g)]=2x−(−120).
2x=−40+(−120),x=80kJ/mol.
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