Question

The standard enthalpy of formation of carbon - di - sulphide $\left(l\right)$ is:
Given the standard enthalpy of
combustion of carbon (s) , sulphur (s) & carbon - di - sulphide $\left(l\right)$ are : $-393.3,-293.72$ and
$-1108.76kJmo{l}^{-1}$ respectively.

• A. 128.02 kJ
• B. 456.21kJ
• C. 232.56 kJ
• D. 871.25 kJ

Answer 1

The correct option is A 128.02 kJ

As given,

$C+O_2\to C{O}_2+393.3$

$2S+2O_2\to 2S{O}_2+293.72\ast 2$

$C{S}_2+3O_2\to C{O}_2+2S{O}_2+1108.76$

by using these reaction data,

$C+2S\to C{S}_2-128.02kJ$