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Question

The standard enthalpy of formation of octane (C8H18) is 250 kJ/mol. Calculate the enthalpy of combustion of C8H18. Given that enthalpy of formation of CO2(g) and H2O(l) are 394 kJ/mol and 286 kJ/mol respectively.

A
5200 kJ/mol
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B
5726 kJ/mol
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C
5476 kJ/mol
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D
5310 kJ/mol
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Solution

The correct option is C 5476 kJ/mol
According to the question,
8C(graphite)+9H2(g)C8H18(g); ΔHf=250 kJ/mol ......(i)C(graphite)+O2(g)CO2(g); ΔHf=394 kJ/mol ......(ii)H2(g)+12O2(g)H2O(l); ΔHf=286 kJ/mol......(iii)
The reaction of combustion of octane is C8H18(g)+252O28CO2(g)+9H2O(l) .....(iv)
The equation(iv) can be obtained by 8×equation(ii)+9×equation(iii)equation(i)
ΔHcombustion=8×(394)+9×(286)(250)=5476 kJ/mol

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