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Question

The standard enthalpy of formation of propene, C3H6 is +20.6 kJ mol1. The heats of formation of CO2(g) and H2O(l) are -394 kJ mol1. and -285.8 kJ mol1.


Calculate the heat of combustion of one mole of C3H6.

A
1721.2 kJ mol1.
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B
-1978.1 kJ mol1.
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C
2060.0 kJ mol1.
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D
2221.6 kJ mol1.
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Solution

The correct option is A 2060.0 kJ mol1.
C3H6+92O23CO2+3H2O

3C+3H2C3H6 ΔH= 20.6 kJ mol1.

C+O2CO2 ΔH=394 kJ mol1.

H2+12O2H2O ΔH=285.8 kJ mol1.

(ΔHC)C3H6=[3ΔHCO2+3ΔHf(H2O)ΔHf(C3H6)]

=[3×(394)3(285.8)20.6]

(ΔHC)C3H6= 2060 kJ mol1.

Hence, the correct option is C.

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