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Question

The standard enthalpy of formation of propene, C3H6 is +20.6kJ/mole. Calculate the heat of combustion of one mole of C3H6. The heats of formation of CO2(g) and H2O(l) are 394kJ/mole and 285.8kJ/mole
[Give your answer in terms of magnitude of the heat of combustion]

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Solution

C3H6+92O23CO2+3H2O

3C+3H2C3H6ΔH=+20.6kJ/mole

C+O2CO2ΔH=394kJ/mole

H2+12O2H2OΔH=285.8kJ/mole

(ΔHC)C3H6=[3ΔHCO2+3ΔHf(H2O)ΔHf(C3H6)]

=[3×(394)+3(285.8)20.6]

(ΔHC)C3H6=2060kJ/mole

|(ΔHC)C3H6|=|2060|=2060

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