MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equation of Circle with (h,k) as Center

The standard ...

Question

The standard equation of circle at origin is

A

x^{2} + y^{2} = r^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

x^{2} - y^{2} = r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

x^{2} + y^{2} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

x^{2} + y^{2} = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $x^{2} + y^{2} = r^{2}$
The standard equation of circle at origin is $x^{2} + y^{2} = r^{2}$
Example: A circle with its center at the origin $(0, 0)$ , and radius $r$ has the equation $x^{2} + y^{2} = r^{2}$ . We'll know if a given point is on the circle if the coordinates of that point satisfy the equation.

Suggest Corrections

thumbs-up

0

Similar questions

Q. The equation to the locus of the midpoints of chords of the circle

x^{2} + y^{2} = r^{2}

having a constant length 2l is

x^{2} + y^{2} - 8 x = 0

\frac{x^{2}}{9} - \frac{y^{2}}{4} = 1

intersect at point

A

B

. The equation of circle with

A B

as diameter is:

Q. Equation of the circle passing through the point

(1, 1)

and point of intersection of circles

x^{2} + y^{2} = 6

x^{2} + y^{2} - 6 x + 8 = 0

Q. The equation of director circle of the circle

x^{2} + y^{2} = a^{2}

The circle $x^{2} + y^{2} - 8 x = 0$ and hyperbola $\frac{x^{2}}{9} - \frac{y^{2}}{4} = 1$ intersect at the points A and B.
Equation of the circle with AB as its diameter is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Definition and Standard Forms

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Equation of Circle with (h,k) as Center

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon