Question

The standard form of $\frac{-8}{-36}$ is _____.

Answer 1

A rational number is said to be in the standard form if its denominator is a positive integer and the numerator and denominator have no common factor other than $1$.

Given fraction is $\frac{-8}{-36}$

HCF of $-8$ and $-36$ is $-4$

Then, divide both numerator and denominator by $-4$.

$$\begin{gathered} =\frac{(-8÷-4)}{(-36÷-4)} \\ =\frac{2}{9} \end{gathered}$$

Hence, the answer is $\frac{2}{9}$.