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Rational Numbers in Standard Form

The standard ...

Question

Question 07

The standard form of $\frac{- 48}{60}$ is

(a) $\frac{48}{60}$

(b) $\frac{- 60}{48}$

(c) $\frac{- 4}{5}$

(d) $\frac{- 4}{- 5}$

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Solution

Given rational number is $\frac{- 48}{60}$
For standard/simplest form divide numerator and denominator by their HCF i.e. $\frac{- 48 \div 12}{60 \div 12} = \frac{- 4}{5}$
Hence the standard form of $\frac{- 48}{60}$ is $\frac{- 4}{5}$

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Similar questions

Q. The standard form of

- \frac{48}{60}

In the adjoining figure, AOB is a straight line. If x : y : z=4:5 :6, then y =?

(a) $60^{\circ}$

(b) $80^{\circ}$

(c) $48^{\circ}$

(d) $72^{\circ}$

$\frac{1}{2}$ , $\frac{2}{3}$ , $\frac{3}{4}$ and $\frac{4}{5}$ as like fractions are $\frac{40}{60}$ , $\frac{30}{60}$ , $\frac{45}{60}$ and $\frac{48}{60}$ repectively.

Q. In the adjoining figure, AOB is a straight line. If x : y : z = 4 : 5 : 6, then y = ?
(a) 60°
(b) 80°
(c) 48°
(d) 72°

The angles of a quadrilateral are in the ratio 3 : 4 : 5 : 6. The smallest of these angles is

(a) $45^{\circ}$

(b) $60^{\circ}$

(c) $36^{\circ}$

(d) $48^{\circ}$

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Rational Numbers in Standard Form

Standard VII Mathematics

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