Question

The standard free energies of formation in the gaseous state of methanol, dimethyl ether and water are $-38.7,-27.3$ and $-54.6kcal$ respectively. Is the transformation of methanol to dimethyl ether water in gaseous state possible?
$2{CH}_{3}OH⟶{CH}_{3}O{CH}_3+H_{2}O$

Answer 1

The heat of formation of dimethyl ether from methanol = heat of formation of dimethyl ether + heat of formation of water - 2$\times$ heat of formation of methanol

Heat of formation of dimethyl ether from methanol =$-27.3+(-54.6)-2\ast (-38.7)=-.5kcal$

since the process the exothermic,

hence we can say transformation is possible.