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Gibbs Free Energy & Spontaneity

The standard ...

Question

The standard Gibbs energy change for a gaseous reaction at 27 is X Kcal. If equilibrium constant a reaction is 100 and R is 2 cal $K^{- 1} {m o l}^{- 1}$ . Then X is:

-2.7636

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2.7636

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+ 807

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- 807

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Solution

The correct option is B -2.7636
$Δ G^{o} = - R T l n K$
$∴ X = - 2 \times 300 \times l n 100$
$∴ X = - 2.7636 K c a l$

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