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Question

The standard heat of formation values of SF6(g) ,S(g) and F(g) are: 1100,275 and 80 KJ mol1 respectively. Then the average S - F bond energy in SF6 is:


  1. 301 KJ mol-1

  2. 320 KJ mol-1

  3. 309 KJ mol-1

  4. 280 KJ mol-1


Solution

The correct option is C

309 KJ mol-1


S(g) + 6F(g)  SF6(g);      ΔHr = 1100 KJ mol1

S(S)    S(g);                       ΔH = +275 KJ mol1

12 F2(g)                              ΔH = 80 KJ mol1

Therefore heat of formation = Bond energy of reactant - Bond energy of product - 1100 = [275 + 6 × 80]  [6 × S  F]

Thus bond energy of S  F = 309 Kj mol1

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