The standard heats of formation of - CCl - 4 - g - - H - 2 O - g - - CO - 2 - g - and HCl - g at - 298 K - arell -25-5-57-8-94-1 and-A- -82-8 kcal mol -1B- -82-8 kcal mol -1C- -41-4 kcal mol -1D- -41-4 kcal mol -1

The correct option is C 41.4 kcal mol^ 1We are given the standard heat of formation of nbsp; reactant and products. we know that, Δ H^0_r=∑Δ_fH^0 (products) ...

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Standard XII

Chemistry

Heat of Formation

The standard ...

Question

The standard heats of formation of $C C l_{4} (g), H_{2} O (g), C O_{2} (g) a n d H C l (g) a t 298 K a r e - 25.5, - 57.8, - 94.1 a n d - 22.1 k c a l m o l^{- 1} r e s p e c t i v e l y . Δ H^{0} (298 K) f o r t h e r e a c t i o n$ $C C l_{4} (g) + 2 H_{2} O (g) \to C O_{2} (g) + 4 H C l (g)$

+ 82.8 k c a l m o l^{- 1}

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- 82.8 k c a l m o l^{- 1}

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+ 41.4 k c a l m o l^{- 1}

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- 41.4 k c a l m o l^{- 1}

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Solution

The correct option is D $- 41.4 k c a l m o l^{- 1}$
We are given the standard heat of formation of reactant and products.
we know that,
$Δ H_{r}^{0} = \sum Δ_{f} H^{0} (p r o d u c t s) - \sum Δ_{f} H^{0} (r e a c t a n t s)$

putting all the values,
$= - 94.1 + 4 (- 22.1) - (- 25.5 - 2 \times 57.8) k c a l m o l^{- 1} = - 41.4 k c a l m o l^{- 1}$

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Similar questions

Q. The standard heats of formation of

C C l_{4} (g), H_{2} O (g), C O_{2} (g) a n d H C l (g) a t 298 K a r e - 25.5, - 57.8, - 94.1 a n d - 22.1 k c a l m o l^{- 1} r e s p e c t i v e l y . Δ H^{0} (298 K) f o r t h e r e a c t i o n

C C l_{4} (g) + 2 H_{2} O (g) \to C O_{2} (g) + 4 H C l (g)

Q. The standard heats of formation at

298 K

for

C {C l}_{4} (g), H_{2} O (g), {C O}_{2} (g)

and

H C l (g)

are

- 25.5, - 57.8, - 94.1

and

- 22.1

k c a l

{m o l}^{- 1}

respectively. Calculate

Δ H_{298}^{o}

for the reaction.

C {C l}_{4} (g) + H_{2} O (g) ⟶ {C O}_{2} (g) + 4 H C l (g)

Q. Calculate the heat of combustion of

1

mole of

C_{2} H_{4} (g)

to form

{C O}_{2} (g)

and

H_{2} O (g)

398 K

and

1

atmosphere, given that the heats of formation of

{C O}_{2} (g), H_{2} O (g)

and

C_{2} H_{4} (g)

are

- 94.1, - 57.8

and

+ 12.5

k c a l

{m o l}^{- 1}

respectively.

Q. The standard heat of formation at

298 K

for

C {C l}_{4} (g), H_{2} O (g), {C O}_{2} (g), H C l (g)

are

- 25.5, - 57.8, - 94, 1, - 22.1

k c a l {m o l}^{- 1}

respectively, calculate

Δ H_{298}^{o}

for the reaction,

C {C l}_{4} (g) + 2 H_{2} O (g) ⟶ {C O}_{2} (g) + 4 H C l (g)

Q. Given:

C (s) + O_{2} (g) \to C O_{2}, (g); △ H = - 94.3 k c a l / m o l

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g); △ H = - 67.4 k c a l / m o l

O_{2} (g) \to 2 O (g); △ H = 117.4 k c a l / m o l

C O (g) \to C (g) + O (g); △ H = 230.6 k c a l / m o l

Calculate

△ H

for

C (s) \to C (g)

k c a l / m o l

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Heat of Formation

Standard XII Chemistry

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The standard heats of formation of CCl4 (g), H2O (g), CO2 (g) and HCl (g) at 298K are−25.5,−57.8,−94.1 and−22.1 kcal mol−1 respectively. ΔH0 (298K) for the reaction CCl4 (g)+2H2O (g)→CO2 (g)+4HCl (g)

The correct option is D −41.4 kcal mol−1 We are given the standard heat of formation of reactant and products. we know that, ΔH0r=∑ΔfH0 (products)−∑ΔfH0 (reactants) putting all the values, =−94.1+4(−22.1)−(−25.5−2×57.8) kcal mol−1 =−41.4 kcal mol−1

The standard heats of formation of $C C l_{4} (g), H_{2} O (g), C O_{2} (g) a n d H C l (g) a t 298 K a r e - 25.5, - 57.8, - 94.1 a n d - 22.1 k c a l m o l^{- 1} r e s p e c t i v e l y . Δ H^{0} (298 K) f o r t h e r e a c t i o n$ $C C l_{4} (g) + 2 H_{2} O (g) \to C O_{2} (g) + 4 H C l (g)$