The standard heats of formation of CH4(g),CO2(g) and H2O(l) are −76.2,−398.8,−241.6kJmol−1. Calculate amount of heat evolved by burning 1m3 of methane measured under normal (STP) conditions (nearest number in MJ).
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Solution
R1:C(s)+2H2(l)→CH4(g) ; ΔH1=−76.2kJmol−1
R2:C(s)+O2(g)→CO2(g) ; ΔH2=−398.8kJmol−1
R3:H2(g)+12O2(g)→H2O(l) ; ΔH3=−241.6kJmol−1
Now, burning methane
R4:CH4(g)+2O2(g)→CO2(g)+2H2O(l) ; ΔH4
And
R4=−R1+R2+2R3
According to Hess's Law of constant heat summation,
ΔH4=−ΔH1+ΔH2+2ΔH3
ΔH4=76.2−398.8+2×(−241.6)=−805.8kJmol−1
1 mole of methane gas at STP occupies 22.4 l volume (assuming ideal gas behavior)
22.4l→1mole
1000l(1m3)→?mole
⇒1m3 of methane =100022.4 mole of methane
Therefore, the heat evolved by burning 1m3 of methane