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Question

The standard heats of formation of CH4(g),CO2(g) and H2O(l) are 76.2,398.8,241.6kJmol1. Calculate amount of heat evolved by burning 1 m3 of methane measured under normal (STP) conditions (nearest number in MJ).

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Solution

R1:C(s)+2H2(l)CH4(g) ; ΔH1=76.2kJmol1
R2:C(s)+O2(g)CO2(g) ; ΔH2=398.8kJmol1
R3:H2(g)+12O2(g)H2O(l) ; ΔH3=241.6kJmol1
Now, burning methane
R4:CH4(g)+2O2(g)CO2(g)+2H2O(l) ; ΔH4
And
R4=R1+R2+2R3
According to Hess's Law of constant heat summation,
ΔH4=ΔH1+ΔH2+2ΔH3
ΔH4=76.2398.8+2×(241.6)=805.8 kJmol1
1 mole of methane gas at STP occupies 22.4 l volume (assuming ideal gas behavior)
22.4l1mole
1000l(1m3)?mole
1m3 of methane =100022.4 mole of methane
Therefore, the heat evolved by burning 1 m3 of methane

=100022.4×805.8

=35973kJ=35.973MJ
Answer = 36

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