wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The standard hydrolysis constant of anilinium acetate at 25 C is (Ka(CH3COOH)=1.8×105 M, Kb(Aniline)=4.6×1010 )

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.21
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.35
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.21
Given: (Ka(CH3COOH)=1.8×105 M, Kb(Aniline)=4.6×1010 )
PhNH+3CH3COO+H2OPhNH2+CH3COOH+H2O
PhNH2+H2OPhNH+3+OH
CH3COOH+H2OCH3COO+H3O+
From the hydrolysis of salt, we know,
Kh=KwKaKb
Kh=1.0×1014(1.8×105)(4.6×1010)=1.21

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon