The standard molar heat of formation of ethane, CO2 and water (l) are respectively −21.1, −94.1 and −68.3Kcal. The standard molar heat of combustion of ethane will be:
A
-372 Kcal
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B
- 162 Kcal
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C
- 240 Kcal
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D
-183. 5 Kcal
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Solution
The correct option is D -372 Kcal
Solution:- (A) −372kcal
Combustion of ethane-
C2H6(s)+72O2(g)⟶2CO2(g)+3H2O(l)
ΔH0=∑ΔH0f(product)−∑ΔH0f(reactant)
∴ΔH0=(2×(−94.1)+3×(−68.3))−(−21.1+0)
⇒ΔH0=−393.1+21.1=−372kcal
Hence the standard molar heat of combustion will be −372kcal.