The standard reduction electrode potentials of three metals $A, B$ and $C$ are $+ 0.5 V, - 3.0 V$ and $+ 1.2 V$ respectively. The order of reducing power of these metals is

B > A > C

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A > B > C

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C > B > A

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A > C > B

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Solution

The correct option is B $B > A > C$
The metal with least standard reduction electrode potential has the highest reducing power and vice-versa. Therefore, the order of the reducing power of these metals is $B > A > C$ .

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+ 0.5 V, - 3.0 V & - 1.2 V

E^{\circ}

X

Y

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- 1.2 V

+ 0.5 V

- 3.0 V

The standard electrode potential values of the elements A,B and C are 0.68, 2.5V and 0.5V respectively the order of their reducing power is :

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