You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrochemical Series

The standard ...

Question

The standard reduction potential at 298 K for following half reactions are given against each
$Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s); - 0.762$
$C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s); - 0.740$
$2 H^{⨁} (a q) + 2 e^{-} ⇌ H_{2} (g); 0.000$
$F e^{3 +} (a q) + 3 e^{-} ⇌ F e^{2 +} (a q); 0.770$
Which is the strongest reducing agent ?

Z n (s)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C r (s)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} (s)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e^{2 +} (a q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $Z n (s)$
$Z n$ is the strongest reducing agent among the given options. The substance having a smaller value of reduction potential are better-reducing agents.

Suggest Corrections

Similar questions

Z n^{2 +} (a q) + 2 e ⇌ Z n (s) - 0.762

C r^{3 +} (a q) + 2 e ⇌ C r (s) - 0.740

2 H^{+} (a q) + 2 e ⇌ H_{2} (g) 0.000

F e^{3 +} (a q) + 2 e ⇌ F e^{2 +} (a q) 0.770

Z n_{(a q)}^{2 +} + 2 e^{-} ⇌ Z n_{(s)}

E^{\circ}

- 0.762 V

C r_{(a q)}^{3 +} + 3 e^{-} ⇌ C r_{(s)}

E^{\circ}

- 0.740 V

2 H_{(a q)}^{+} + 2 e^{-} ⇌ H_{2 (g)}

E^{\circ}

0.000 V

F e_{(a q)}^{3 +} + e^{-} ⇌ F e_{(s)}^{2 +}

E^{\circ}

0.770 V

25^{\circ} C

Z n^{2 +} (a q .) + 2 e^{-} ⇌ Z n (s); - 0.762

C r^{3 +} (a q .) + 3 e^{-} ⇌ C r (s); - 0.740

2 H^{+} + 2 e^{-} ⇌ H_{2} (g); 0.00

F e^{3 +} + e^{-} ⇌ F e^{2 +}; 0.77

298 K

Z n^{2 +} (a q) + 2 e ⇌ Z n (s); - 0.762 V

C r^{3 +} (a q) + 3 e ⇌ C r (s); - 0.740 V

2 H^{+} (a q) + 2 e ⇌ H_{2} (g); 0.00 V

F e^{3 +} (a q) + e ⇌ F e^{2 +} (a q); 0.770 V

298 K

{Z n}^{2 +} (a q) + 2 e^{-} ⇌ Z n (s) - 0.762

{C r}^{3 +} (a q) + 3 e^{-} ⇌ C r (s) - 0.74

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g) + 0.00

{F e}^{3 +} (a q) + e^{-} ⇌ {F e}^{2 +} (a q) + 0.77

Join BYJU'S Learning Program