The standard reduction potential data at 25oC is given below- Eo Fe3- Fe2-0-77V- Eo Fe2- Fe-0-44V Eo Cu2- Cu-0-34V Eo Cu- Cu-0-52V Eo-O2g-4H-4e- 2H20-1-23V- Eo-O2g-2H2O-4e- 40H-0-40V Eo Cr3- Cr-0-74V- Eo Cr2- Cr-0-91VMatch E0 of the redox pair in List 1 with the values given in List 2 and select the correct answer using the code given below the lists-

(A) ΔG_Fe^3+/Fe^o=ΔG_Fe^+3/Fe^2+^o+ΔG_Fe^2+/Fe^o ⇒ #160; #160; 3×FE_(Fe^+3/Fe)^o= 1×FE_(Fe^+3/Fe^+2)^o+( 2×FE_Fe^+2/Fe^o) ⇒ #160;E_Fe ...

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Byju's Answer

Standard XII

Chemistry

Gibb's Energy and Nernst Equation

The standard ...

Question

The standard reduction potential data at $25^{o} C$ is given below:

$E^{o} (F e^{3 +}, F e^{2 +}) = + 0.77 V$ ;
$E^{o} (F e^{2 +}, F e) = - 0.44 V$
$E^{o} (C u^{2 +}, C u) = + 0.34 V$
$E^{o} (C u^{+}, C u) = + 0.52 V$
$E^{o} [O_{2} (g) + 4 H^{+} + 4 e^{-} \to 2 H_{2} 0] = + 1.23 V$ ;
$E^{o} [O_{2} (g) + 2 H_{2} O + 4 e^{-} \to 40 H^{-}] = + 0.40 V$
$E^{o} (C r^{3 +}, C r) = - 0.74 V$ ;
$E^{o} (C r^{2 +}, C r) = - 0.91 V$
Match $E^{0}$ of the redox pair in List 1 with the values given in List 2 and select the correct answer using the code given below the lists.

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Solution

$(A)$ $Δ G_{F e^{3 + / F e}}^{o} = Δ G_{F e^{+ 3 / F e^{2 +}}}^{o} + Δ G_{F e^{2 + / F e}}^{o}$
$\Rightarrow - 3 \times F E_{(F e^{+ 3} / F e)}^{o} = - 1 \times F E_{(F e^{+ 3} / F e^{+ 2})}^{o} + (- 2 \times F E_{F e^{+ 2} / F e}^{o})$
$\Rightarrow E_{F e^{+ 3} / F e}^{o} = - 0.04 V$
$(B)$ $O_{2} (g) + 2 H_{2} O + 4 e^{-} \to 4 O H^{-} \Rightarrow E^{o} = 0.40 V$ ......... $i$ )
$2 H_{2} O \to O_{2} (g) + 4 H^{+} + 4 e^{-} \Rightarrow E^{o} = - 1.23 V$ .....( $i i$ )
So, $4 H_{2} O ⇌ 4 H^{+} + 4 O H^{-}$ ........ ( $i i i$ )
$E^{o}$ for $I I I^{r d}$ reduction $= 0.40 - 1.23 = - 0.83 V$ .
$(C)$ $Δ G_{(C u^{+ 2} / C u)}^{o} = Δ G_{(C u^{+ 2} / C u^{+})}^{o} + Δ G_{(C u^{+} / C u)}^{o}$
$- 2 \times F E_{C u^{+ 2} /}^{o} C u = - 1 \times F E_{C u^{+ 2} /}^{o} C u + + (- 1 \times F \times E_{C u^{+} / C u}^{o})$
$\Rightarrow E_{C u^{+ 2} / C u}^{o} = - 0.18 V$
$(D)$ $Δ G_{C r^{+ 3} / C r^{+ 2}}^{o} = Δ G_{C r^{+ 3} / C r}^{o} + Δ G_{C r / C r^{+ 2}}^{o}$
$- 1 \times F \times E_{C r^{+ 3} / C r^{+ 2}}^{o} = - 3 \times F \times E_{C r^{+ 3} /}^{o} C r + (- 2 \times F \times E_{C r / C r^{+ 2}}^{o})$

$\Rightarrow E_{C r^{+ 3} / C r^{+ 2}}^{o} = - 0.4 V$ .

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The standard reduction potential data at $25^{\circ} C$ is given below.

$E^{\circ} (F e^{3 +} / F e^{2 +}) = 0.77 V; E^{\circ} (F e^{2 +} / F e) = - 0.44 V; E^{\circ} (C u^{2 +} / C u) = 0.34 V; E^{\circ} (C u^{+} / C u) = + 0.52 V; E^{\circ} (O_{2} (g) + 4 H^{+} + 4 e^{-}) \to 2 H_{2} O = + 1.23 V; E^{\circ} (O_{2} (g) + 2 H_{2} O + 4 e^{-}) \to 4 O H^{-} = + 0.40 V E^{\circ} (C r^{3 +} / C r) = - 0.74 V; E^{\circ} (C r^{2 +} / C r) = + 0.91 V$

Match $E^{\circ}$ of the rebox pair in Column I with the values given in Column II and select the correct answer using the code given below the lists.

$\begin{matrix} C o l u m n I & C o l u m n I I P . E^{\circ} (F e^{3 +} / F e) & 1. - 0.18 V Q . E^{\circ} (4 H_{2} O ⇌ 4 H^{+} + 4 O H^{-}) & 2. - 0.4 V R . E^{\circ} (C u^{2 +} + C u \to 2 C u^{+}) & 3. - 0.04 V S . E^{\circ} (C r^{3 +} / C r^{2 +}) & 4. - 0.83 V \end{matrix}$

The standard reduction potential data at $25^{\circ} C$ is given below.

Match $E^{\circ}$ of the rebox pair in Column I with the values given in Column II and select the correct answer using the code given below the lists.