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Application of Electrolysis

The standard ...

Question

The standard reduction potential of $A g^{+} | A g$ electrode is $0.80 v o l t$ . Calculate the standard electrode potential of $C l^{-} | A g C l | A g$ at $25^{\circ} C$ . Given solubility product, $K_{s p} (A g C l) = 1.8 \times 10^{- 10}$ .

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Solution

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$E_{c e l l}^{\circ} = 0.0591 \times log [A g^{+}] [C l^{-}] = 0.0591 log K_{s p} (A g C l)$
$E_{c e l l}^{\circ} = - 0.576 v o l t$
$E_{c e l l}^{\circ} =$ Oxide. pot. anode $+$ Red. pot. cathode
Red. pot. cathode $[C l^{-}] | A g C l | A g] = - 0.576 - (- 0.80)$
$= - 0.576 + 0.80 = 0.224 v o l t$ .

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