The standard reduction potential of $C u^{2 +} (a q)$ is $+ 0.34 V$ . What is the oxidation potential of Cu(s)?

+ 0.68 V

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+ 0.34 V

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- 0.34 V

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- 0.68 V

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Solution

The correct option is C $- 0.34 V$
Reduction reaction: $C u^{2 +} + 2 e^{-} \to C u, E^{0} = 0.34 V$
Oxidation reaction: $C u \to C u^{2 +} + 2 e^{-}, E^{0} = - 0.34 V$

Therefore, oxidation potential is $- 0.34 V$

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Similar questions

Q. What is the oxidation potential of

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, if the standard reduction potential of

{C u}^{2 +} (a q)

+ 0.34 V

Q. The standard reduction potential for

C u^{2 +} / C u

+ 0.34 V

. The reducing potential at

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{[C u^{2 +}] a t p H 14 i s 10^{- 19}}

Q. Estimate the standard reduction potential for the copper/copper sulphide electrode.

For

C u S, K_{s p} = 8.5 \times 10^{- 36}, E_{C u | C u^{2 +}}^{⊖} = - 0.34 V

The standard reduction potential for $C u^{2 +} | C u$ is $+ 0.34 V$ . Calculate the reduction potential at pH $= 14$ for the above couple if $K_{s p}$ of $C u (O H)_{2}$ is $1.0 \times 10^{- 19}$ .

Q. The cell reaction of a cell is:

M g (s) + c u^{2 +} (a q) ⇌ C u (s) + M g^{2 +} (a q)

If the standard reduction potentials of

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respectively. The emf of the cell is:

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The standard reduction potential of Cu2+(aq) is +0.34V. What is the oxidation potential of Cu(s)?

The correct option is C −0.34VReduction reaction: Cu2++2e−→Cu,E0=0.34VOxidation reaction: Cu→Cu2++2e−,E0=−0.34VTherefore, oxidation potential is −0.34V

The standard reduction potential of $C u^{2 +} (a q)$ is $+ 0.34 V$ . What is the oxidation potential of Cu(s)?

The correct option is C $- 0.34 V$
Reduction reaction: $C u^{2 +} + 2 e^{-} \to C u, E^{0} = 0.34 V$
Oxidation reaction: $C u \to C u^{2 +} + 2 e^{-}, E^{0} = - 0.34 V$

Therefore, oxidation potential is $- 0.34 V$