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Applications of Radius of Curvature

The standard ...

Question

The standard reduction potential of $T i O^{2 +}$ and $T i^{3 +}$ are given by.Find the standard reduction potential of $T i O^{2 +}$ to $T i$ :

T i O^{2 +} + 2 H^{+} + e^{-} ⟶ T i^{3 +} + H_{2} O

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E^{o} = 0.10 V

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T i^{3 +} + 3 e^{-} ⟶ T i

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E^{o} = - 1.21 V

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Solution

The correct option is A $T i O^{2 +} + 2 H^{+} + e^{-} ⟶ T i^{3 +} + H_{2} O$
The reaction for same is
$T i O^{2 +} ⟶ T i O^{3 +}$
$o . s = x - 2 = + 2$
$x = + 4 + 3     $
$1 e^{-}$ transfer
balancing O atom with water
$T i O^{2 +} + e^{-} \to T i^{3 +} + H_{2} O$
Balancing hydrogen on both sides,
${T i O}^{2 +} + 2 H^{+} + e^{-} \to {T i}^{3 +} + H_{2} O$

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Similar questions

T i O^{2 +}

T i^{3 +}

T i O^{2 +} + 2 H^{+} + e^{-} \to T i^{3 +} + H_{2} O

E^{0} = 0.10 V

T i^{3 +} + 3 e^{-} \to T i

E^{0} = - 1.21 V

T i O^{2 +}

T i

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s); E^{o} = - 0.762 V

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s); E^{o} = + 0.762 V

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g); E^{o} = + 0.00 V

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q); E^{o} = + 0.770 V

C o^{3 +} + e^{-} \to C o^{2 +}; E^{o} = + 1.81 V

P b^{4 +} + 2 e^{-} \to P b^{2 +}; E^{o} = + 1.67 V

C e^{4 +} + e^{-} \to C e^{3 +}; E^{o} = + 1.61 V

B i^{3 +} + 3 e^{-} \to B i; E^{o} = + 0.20 V

{F e}^{3 +} + {3 e}^{-} ⟶ F e; E^{o} = - 0.036 v o l t

{F e}^{2 +} + {2 e}^{-} ⟶ F e; E^{o} = - 0.440 v o l t

E^{o}

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}

F e^{2 +} + 2 e^{-} \to F e, E^{o} = - 0.440

F e^{3 +} + 3 e^{-} \to F e, E^{o} = - 0.036

(E^{o})

F e^{3 +} + e^{-} \to F e^{2 +}

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