CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The standard reduction potentials for the following reaction are
Zn2++2eZn;(0.762V)
Cr3++3eCr;(0.74V)
2H++2eH2;(0.0V)
Fe3++eFe2+;(0.77V)
The reducing powers of these species are in the order:

A
Zn>Cr>H2>Fe2+
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Fe2+>H2>Cr>Zn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
H2>Zn>Cr>Fe2+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
H2>Fe2+>Cr>Zn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Zn>Cr>H2>Fe2+
The order of standard reduction potentials are: 0.77V>0.0V>0.74V>0.762V. As the value of standard reduction potential becomes less positive and more negative, the value of reducing power increases.

Hence the reducing power decreases in the order: Zn>Cr>H2>Fe2+.
So, option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrochemical series_tackle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon