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Question

The standard reduction potentials for the following reaction are
Zn2++2eZn;(0.762V)
Cr3++3eCr;(0.74V)
2H++2eH2;(0.0V)
Fe3++eFe2+;(0.77V)
The reducing powers of these species are in the order:

A
Zn>Cr>H2>Fe2+
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B
Fe2+>H2>Cr>Zn
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C
H2>Zn>Cr>Fe2+
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D
H2>Fe2+>Cr>Zn
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Solution

The correct option is A Zn>Cr>H2>Fe2+
The order of standard reduction potentials are: 0.77V>0.0V>0.74V>0.762V. As the value of standard reduction potential becomes less positive and more negative, the value of reducing power increases.

Hence the reducing power decreases in the order: Zn>Cr>H2>Fe2+.
So, option A is correct.

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