The standard reduction potentials for the following reaction are Zn2++2e−→Zn;(−0.762V) Cr3++3e−→Cr;(−0.74V) 2H++2e−→H2;(0.0V) Fe3++e−→Fe2+;(0.77V) The reducing powers of these species are in the order:
A
Zn>Cr>H2>Fe2+
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B
Fe2+>H2>Cr>Zn
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C
H2>Zn>Cr>Fe2+
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D
H2>Fe2+>Cr>Zn
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Solution
The correct option is AZn>Cr>H2>Fe2+ The order of standard reduction potentials are: 0.77V>0.0V>−0.74V>−0.762V. As the value of standard reduction potential becomes less positive and more negative, the value of reducing power increases.
Hence the reducing power decreases in the order: Zn>Cr>H2>Fe2+.