The standard reduction potentials (in V) of a few metal ion/metal electrodes are given below.
The reducing strength of the metals follows the order.

Ag > Cu > Pb > Cr

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Cr > Pb > Cu > Ag

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Pb > Cr > Ag > Cu

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Cr > Ag > Cu > Pb

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Solution

The correct option is B Cr > Pb > Cu > Ag
Any element having low value of reduction potential is good reducing agent. So,
Cr > Pb > Cu > Ag

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Similar questions

K^{+} / K = - 2.93 V, A g^{+} / A g = 0.80 V

M g^{2 +} / M g = - 2.37 V, C r^{3 +} / C r = - 0.74 V

E_{C u / C u^{+ +}}^{\circ} = - 0.34

E_{C r / C r^{+ + +}}^{\circ} = 0.74

E_{P b / P b^{+ +}}^{\circ} = 0.126

K^{+} / K = - 2.93 V, A g^{+} / A g = 0.80 V,

H g^{2 +} / H g = 0.79 V, M g^{2 +} / M g = - 2.37 V, C r^{3 +} / C r = - 0.74 V

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