The standing waves set upon a string are given by y=4sin(πx12)cos(52πt) If x and y are in centimetres and t is in seconds, what is the amplitude of the particle at x=2cm?
A
12cm
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B
4cm
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C
2cm
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D
1cm
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Solution
The correct option is B2cm Putting x=2 cm in the given standing wave equation, we get y=4sin(π6)sin(52πt)=2sin(52πt). Thus, the amplitude is 2cm