You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Chemistry

Uses of Radioactive Substances

The starting ...

Question

The starting isotope and the end product isotope of actinium series are:

_{88}^{227} A c

and

_{82}^{208} P b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{92}^{235} U

and

_{82}^{207} P b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

_{92}^{238} U

and

_{82}^{207} P b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{92}^{235} U

and

_{82}^{208} P b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $_{92}^{235} U$ and $_{82}^{207} P b$
Actinium $(4 n + 3)$ series starts with $_{92}^{235} U$ and as metal, decays finally to $_{82}^{207} P b .$

Suggest Corrections

Similar questions

Q. The isotope

_{92}^{235} U

decays in a number of steps to an isotope of

_{82}^{207} P b

. The groups of particles emitted in this process will be:

_{92}^{235} U

decays with emission of

α

and

β -

particles to form ultimately

_{82}^{207} P b

. How many

α -

and

β -

particles are emitted per atom of

P b

produced?

Q. Estimate the age of a rock which is found to contain

5 \times 10^{- 5}

mL of helium at STP and

3 \times 10^{- 7}

g of uranium. (

T_{50}

_{92}^{238} U

4.51 \times 10^{9}

yr and each

_{92}^{238} U

is converted into

_{82}^{206} P b

Plan

_{92}^{238} U ⟶_{82}^{206} P b + 6 β + 8 α (h e l i u m)

We take the equation

[\frac{[P b]}{[U]} + 1] = (2)^{y}

where

\frac{[P b]}{[U]}

is the molar ratio,

y = \frac{t}{T_{50}}

_{90}^{232} T h

disintegrates to

_{82}^{208} P b

. How many of

β

-particles are evolved?

Q. The total number of

α

and

β

particles emitted in the nuclear reaction:

_{92}^{238} U ⟶

_{82}^{214} P b

are:

Join BYJU'S Learning Program

The starting isotope and the end product isotope of actinium series are:

The correct option is B 23592U and 20782PbActinium (4n+3) series starts with 23592U and as metal, decays finally to 20782Pb.

The correct option is B $_{92}^{235} U$ and $_{82}^{207} P b$
Actinium $(4 n + 3)$ series starts with $_{92}^{235} U$ and as metal, decays finally to $_{82}^{207} P b .$