The state of 2D-stress at a point is given by the following matrix of stresses - - - xx - xy- - xy - yy - 100 30- 30 20 - MPaWhat is the magnitude of maximum shear stress in MPa-

Τ _max= Radius of mohr circle Centre of Mohr circle is (60,0) Radius =√(30^2+40^2)=50 nbsp;⇒τ _max=50 units. ...

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The state of 2D-stress at a point is given by the following matrix of stresses :
$[\begin{matrix} σ_{x x} & σ_{x y} σ_{x y} & σ_{y y} \end{matrix}] = [\begin{matrix} 100 & 30 30 & 20 \end{matrix}]$ MPa

What is the magnitude of maximum shear stress in MPa?

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100

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110

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Solution

The correct option is A 50
$τ_{m a x} =$ Radius of mohr circle Centre of Mohr circle is (60,0)
Radius $= \sqrt{30^{2} + 40^{2}} = 50$
$\Rightarrow τ_{m a x} = 50$ units.

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The state of 2D-stress at a point is given by the following matrix of stresses : [σxxσxyσxyσyy]=[100303020] MPa What is the magnitude of maximum shear stress in MPa?

The correct option is A 50τmax= Radius of mohr circle Centre of Mohr circle is (60,0) Radius =√302+402=50 ⇒τmax=50 units.

The state of 2D-stress at a point is given by the following matrix of stresses :
$[\begin{matrix} σ_{x x} & σ_{x y} σ_{x y} & σ_{y y} \end{matrix}] = [\begin{matrix} 100 & 30 30 & 20 \end{matrix}]$ MPa

What is the magnitude of maximum shear stress in MPa?

The correct option is A 50
$τ_{m a x} =$ Radius of mohr circle Centre of Mohr circle is (60,0)
Radius $= \sqrt{30^{2} + 40^{2}} = 50$
$\Rightarrow τ_{m a x} = 50$ units.