The state of an ideal gas was changed isobarically. The graph depicts three such isobaric lines. Which of the following is true about the pressures of the gas?

P_{1} = P_{2} = P_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P_{1} > P_{2} > P_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P_{1} < P_{2} < P_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P_{1} / P_{2} = P_{3} / P_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $P_{1} > P_{2} > P_{3}$
For constant temperature $P \propto \frac{1}{V}$
$V_{3} > V_{2} > V_{1}$
so $P_{3} < P_{2} < P_{1}$

Suggest Corrections

Similar questions

A plot of volume (V) versus temperature (T) for a gas at constant pressure is a straight line passing through the origin. The plots at different values of pressure are shown in figure. Which of the following order of pressure is correct for this gas?