The state of hybridisation of the central atom in the dimer forms of both $B H_{3}$ and $B e H_{2}$ is respectively:

s p^{2}, s p

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s p^{3}, s p^{2}

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s p^{3}, s p^{3}

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s p^{2}, s p^{3}

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Solution

The correct option is B $s p^{3}, s p^{2}$
Dimer form of $B H_{3} i s B_{2} H_{6}$

Dimer form of $B e H_{2} i s B e_{2} H_{4}$

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Similar questions

The hybridization of central atom in dimer of $B H_{3}$ and $B e H_{2}$ is:

The state of hybridization of boron and oxygen atoms in boric acid $(H_{3} B O_{3})$ are respectively:

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

H_{3} B O_{3}

N O_{3}^{-}, N O_{2}^{+}, N H_{4}^{+}

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