Question

The state of hybridization for the transition state of hydolysis mechanism of $BC{l}_3$ and $S{F}_4$ are respectively:

• A. $s{p}^2$, $s{p}^{3}d$
• B. $s{p}^3$, $sp3$
• C. $s{p}^3$, $s{p}^3{d}^2$
• D. $s{p}^3$, $s{p}^{3}d$

Answer 1

The correct option is C $s{p}^3$, $s{p}^3{d}^2$

Boron trichloride is $s{p}^2$ hybridized with trigonal planar geometry.
In the transition state a molecule of water is coordinated which results in $s{p}^3$ hybridization with tetrahedral geometry.
$S{F}_4$ is $s{p}^{3}d$ hybridized with see saw geometry.
In the transition state, a molecule of water is coordinated which results in square pyramidal geometry.