Question

The state of hybridization of $C_2,C_3,C_5$ and $C_6$ of the hydrocarbon is in the following sequence:

• A. $sp,s{p}^2,s{p}^3$ and $s{p}^2$
• B. $sp,s{p}^3,s{p}^2$ and $s{p}^3$
• C. $s{p}^3,s{p}^2,s{p}^2$ and $sp$
• D. $sp,s{p}^2,s{p}^2$ and $s{p}^3$

Answer 1

Answer: (B)

$sp,s{p}^3,s{p}^2$ and $s{p}^3$

To find the hybridization in hydrocarbons follow given procedure:

Type of bond Hybridization

$C-C$ ${sp}^3$

$C=C$ ${sp}^2$

$C\equiv C$ ${sp}^3$

Hence, $C_2$ has $sp$ hybridization

$C_3$ has ${sp}^3$ hybridization

$C_5$ has ${sp}^2$ hybridization

$C_6$ has ${sp}^3$ hybridization