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Question

The statement P(n) = 4n1 3n is true for which of the following options?

A
n N(1}
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B
n N
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C
only for n7
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D
no natural number
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Solution

The correct option is B n N
For n=1,LHS=41=3 and RHS=3So LHS=RHSP(1) is true.
Let P(k) is true for some natural number k,i.e., 4k13k ...(1)We need to prove that P(k+1) is true whenever P(k) is true.Consider 4k+11=4.4k1 =4(4k1+1)1 =4.(4k1)+41 4.3k+3 (Using (1)] >4.3k >3.3k=3k+1i.e., 4k+113k+1Therefore, P(k+1) is true whenever P(k) is true.Hence, by principal of mathematical induction, P(n) is true for every natural number.


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