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Byju's Answer
Standard XI
Mathematics
Implication
The statement...
Question
The statement
(
p
⇒
q
)
⇔
(
∼
p
∧
q
)
is a
A
tautology
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B
contradiction
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C
Neither (a) nor (b)
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D
None of these
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Solution
The correct option is
C
Neither (a) nor (b)
p
q
∼
p
p
⇒
q
∼
p
∧
q
(
p
⇒
q
)
⇔
(
∼
p
∧
q
)
T
T
F
T
F
F
T
F
F
F
F
T
F
T
T
T
T
T
F
F
T
T
F
F
Hence, given statement is neither tautology nor contradiction.
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