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B
p→(p∨q)
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C
p→(p∧q)
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D
p→(p↔q)
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Solution
The correct option is Bp→(p∨q)
Let us make the truth table for the given statements, as follows: pqp∨qq→pp→(q→p)p→(p∨q)TTTTTTTFTTTTFTTFTTFFFTTT From table we observe p→(q→p) is equivalent to p→(p∨q)