The statement(s) true for a 109% oleum sample is/are:
13.5g of water should be added to completely hydrolyse 150 of sample.
150g of sample is sufficient for oxidation of 105.9g of Cu turnings after hydrolysis.
100g of sample can neutralize 2L of 1.11M of aq. NaOH solution.
Let % of free SO3 in sample is x
then, 109=100+18x80
x = 40%
The mass of H2SO4 formed after hydrolysis =150×109100=163.5 g
Hence mass of water added = (163.5 - 150) = 13.5g
Equivalent of Cu = equivalent of H2SO4
w = 105.9gm
Equivalent of NaOH = Equivalent of H2SO4
2×1.11×1=w48
w = 109 gm
Hence oleum required = 100g