The statement - p - q is equivalent toA- P - qB - p - qC - P - qD - - p - q

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Negation

The statement...

Question

The statement $\sim (p \Rightarrow q)$ is equivalent to

$p \land \sim q$

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$\sim p \land q$

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$p \land q$

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$\sim p \land \sim q$

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Solution

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Similar questions

(p \land \sim q) \lor q \lor (\sim p \land q)

(p \land \sim q) \lor q \lor (\sim p \land q)

(p \land \sim q) \lor q \lor (\sim p \land q)

$\sim (\sim p \land q)$ is logically equivalent to

((p \land q) \lor (p \lor \sim q)) \land (\sim p \land \sim q)

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