The stationary point of $f (x) = e^{x} + e^{- x}$ is

(1, 2)

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(2, 3)

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(1, 3)

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(0, 2)

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Solution

The correct option is D (0, 2)
$f^{'} (x) = e^{x} - e^{- x}$
$f^{'} (x) = 0$ at $x = 0$
$f (0) = 2$

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