The steps to construct $60^{\circ}$ angle is given below. Arrange these steps in the correct sequence.

1. Taking O as centre, draw an arc of any size to cut OA at B.

2. Draw a line segment OA of any suitable length.

3. Join OC and produce it to any point D.

4. With B as centre draw another arc of the same size to cut the previous arc at C.

2,1,4,3

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2,1,3,4

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1,2,3,4

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4,3,1,2

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Solution

The correct option is A
2,1,4,3

The correct sequence for construction of $60^{\circ}$ angle is as follows:

1. Draw a line segment OA of any suitable length.

2. Taking O as centre, draw an arc of any size to cut OA at B.

3. With B as centre draw another arc of the same size to cut the previous arc at C.

4. Join OC and produce it to any point D. Then, ∠DOA = $60^{\circ}$ .

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Choose the correct order.

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5: With O as centre and any suitable radius draw an arc above OA cutting it at a point B.

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What is the measure of ∠AOD?

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Choose the correct order.

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2: With C and D as centres and radius more than half of CD, draw two arcs cutting each other at E. Join OE.

3: With O as centre and any convenient radius, draw an arc cutting OA at B.

4: With B as centre and the same radius, draw an cutting the first arc at C.

5: With C as centre and the same radius, draw an arc cutting again the first arc at D.

Q. Steps for the construct an angle

∠ A B C

equal to a given angle

∠ P Q R

without using protractor is given below. Choose the correct order.
1.Draw another ray BC
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3.Join BN using scale and pencil. extend it to get BA.
4.With M as the centre and radius equal to (XY), draw an arc to cut the arc drawn in previous step.
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6.With B as the centre, draw an arc with radius QX.Name the point of intersection of arc and BC as point M.

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