Question

The steps to convert an irregular class interval into a regular one, are

Step 1: Compute correction factor which is $\frac{\text{upper class limit-lower class limit of previous class interval}}{2}$.

Step 2: This is added to the upper limit and subtracted from the lower limit of each class.

• A. Step 1 is correct, but step 2 is incorrect.
• B. Step 1 is incorrect, but step 2 is correct.
• C. Both steps are correct
• D. Both steps are incorrect.

Answer 1

The correct option is C Both steps are correct

Example:

$\begin{array}{cc}\text{Irregular Class Interval}& \text{Regular Class Interval}\\ 0-99& 0.5-99.5\\ 100-199& 99.5-199.5\\ 200-299& 199.5-299.5\\ 300-399& 299.5-399.5\end{array}$

Here, Correction factor $=\frac{100-99}{2}=0.5$ which is added to the upper limit and subtracted from the lower limit of the class.