The stiffness coefficient $k_{12}$ for the beam shown below is

\frac{E I}{2}

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\frac{E I}{4} E I

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\frac{3}{4} E I

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Solution

The correct option is A $\frac{E I}{2}$

$∴$ $k_{12}$ = Force developed at (1) due to unit displacement at (2) while restraining other displacements.
$k_{12} = \frac{2 E I}{4} = \frac{E I}{2}$

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