The stoichiometric coefficient $n$ in the following reaction is :
$n H_{2} C O_{2} + 2 K M n O_{4} \to n C O_{2} + K_{2} O + 2 M n O + H_{2} O$

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Solution

The stoichiometric coefficient $n$ in the following reaction is $5$ .
The oxidation state of $M n$ changes from $+ 7$ to $+ 2$ i.e. the change is $+ 5$ . Hence, $n = + 5$ which comes from charge balance.
$n H_{2} C O_{2} + 2 K M n O_{4} \to n C O_{2} + K_{2} O + 2 M n O + H_{2} O$
Hence, the balanced chemical reaction is $5 H_{2} C O_{2} + 2 K M n O_{4} \to 5 C O_{2} + K_{2} O + 2 M n O + H_{2} O$ .

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